Question

How do you condense `2[ln x-ln(x+2)-ln(x^2-3)]`?

Answer 1

We use the rule `ln(a) - ln(b) = ln(a/b)`.

`=>2[ln((x/(x + 2))/(x^2- 3))]`

`=> 2ln((x)/((x +2)(x^2- 3)))`

Use the rule `alnn = lnn^a`.

`=>ln((x)/((x + 2)(x^2 - 3)))^2`

Hopefully this helps!