# How do you condense #2[ln x-ln(x+2)-ln(x^2-3)]#?

##### 1 Answer

Dec 3, 2016

We use the rule

#=>2[ln((x/(x + 2))/(x^2- 3))]#

#=> 2ln((x)/((x +2)(x^2- 3)))#

Use the rule

#=>ln((x)/((x + 2)(x^2 - 3)))^2#

Hopefully this helps!