# How do you condense 2ln8+5ln(z-4)?

$\ln \left({8}^{2} {\left(z - 4\right)}^{5}\right)$

#### Explanation:

We have:

$2 \ln 8 + 5 \ln \left(z - 4\right)$

We can use the rule that $x \ln y = \ln {y}^{x}$ to rewrite this:

$\ln {8}^{2} + \ln {\left(z - 4\right)}^{5}$

We can then use the rule that $\ln A + \ln B = \ln \left(A B\right)$ to rewrite:

$\ln \left({8}^{2} {\left(z - 4\right)}^{5}\right)$