Question

How do you condense `2logx-3(logy+2logz)`?

Answer 1

`2logx−3(logy+2logz)=log(x^2/(y^3z^6))`

Explanation:

`2logx−3(logy+2logz)`

= `2logx−3logy-6logz`

= `logx^2−logy^3-logz^6`

= `log(x^2/(y^3z^6))`