How do you condense $3 ln x + 5 ln y – 6 ln z$ ?

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Answer 1 · 2016-06-05T05:33:20

$3lnx+5lny-6lnz=ln((x^3y^5)/(z^6))$

$3lnx+5lny-6lnz$

= $lnx^3+lny^5-lnz^6$

= $ln((x^3y^5)/(z^6))$

How do you condense 3 ln x + 5 ln y – 6 ln z3 ln x + 5 ln y – 6 ln z?