How do you condense $4[ln x + ln(x +5)] - 2 ln(x - 5)$ ?

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Answer 1 · 2016-09-02T21:38:41

$4[lnx+ln(x+5)]-2ln(x-5)=ln((x^4(x+5)^4)/((x-5)^2))$

We should use the identities $loga+log=log(a×b)$ , $loga-log=log(a/b)$ and $nloga=log(a^n)$ .

Hence $4[lnx+ln(x+5)]-2ln(x-5)$

$4lnx+4ln(x+5)-2ln(x-5)$

= $lnx^4+ln(x+5)^4-ln(x-5)^2$

= $ln((x^4(x+5)^4)/((x-5)^2))$

How do you condense 4[ln x + ln(x +5)] - 2 ln(x - 5)4[ln x + ln(x +5)] - 2 ln(x - 5)?