Question

How do you condense `ln2+2ln3-ln18`?

Answer 1

0

Explanation:

Using the 'laws of logarithms ' :

• logx + logy = logxy

• logx - logy =`log(x/y )`

• `logx^n = n logx`

Applying these to this question :

`ln2 + 2ln3 - ln18 = ln2 + ln3^2 -ln18 = ln2 + ln9 - ln18`

`= ln((2xx9)/18) = ln(18/18) = ln1 =0`