How do you condense #lnx-3ln(x+1)#?

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Answer 1 · 2018-04-10T12:35:38

# ln x/(x+1)^3 #

We have an expression:

# ln x - 3ln(x+1) #

We use two properties of logarithms:

# alogb -= logb^a# and #log a-logb -= log(a/b) #

Applying the first property we can write the expression as:

# ln x - ln(x+1)^3 #

And applying the second property we can write the expression as:

# ln (x/(x+1)^3) #