How do you condense #log_4 w - 1/2(log_4 x + 5log_4 y) + 2log_4 z#?

1 Answer
Shwetank Mauria
Apr 6, 2017

#log_4w-1/2(log_4x+5log_4y)+2log_4z=log_4((wz^2)/(sqrt(xy^5)))#

Explanation:

#log_4w-1/2(log_4x+5log_4y)+2log_4z#

= #log_4w-1/2(log_4(x xxy^5)+log_4z^2#

= #log_4w-log_4(xy^5)^(1/2)+log_4z^2#

= #log_4(w/(sqrt(xy^5))xxz^2)#

= #log_4((wz^2)/(sqrt(xy^5)))#

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