How do you condense # log_6 25 - log_6 5 #?

1 Answer
Mar 15, 2016

Answer:

Since the log's are in the same base, you can immediately condense using the rule #log_an - log_am = log_a(n/m)#

Explanation:

#log_6(25) - log_6(5) = log_6(25/5) = log_6(5)#

Practice exercises:

  1. Condense #log_5(x + 4) + log_5(2x - 1)#

Challenge problem:

Using the log rule #log_a(n) = (logn)/(loga)# and the multiplication/division rules shown earlier simplify the following expression completely.

#log_2(20) - log_4(5)#

Hopefully this helps!