How do you condense #log r- log t- 2log s#?

1 Answer
Apr 27, 2018

Answer:

#log(r/(ts^2))#

Explanation:

#"using the "color(blue)"laws of logarithms"#

#•color(white)(x)logx+logyhArrlog(xy)#

#•color(white)(x)logx-logyhArrlog(x/y)#

#•color(white)(x)logx^nhArrnlogx#

#rArrrlogr-(logt+logs^2)#

#=logr-log(ts^2)#

#=log(r/(ts^2))#