How do you condense $log345 – log39$ ?

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Answer 1 · 2016-05-12T16:04:33

$log(115/13)$

$log 345-log 39=log(345/39)=log((cancel(3)xx5xx23)/(cancel(3)xx13)))=log(115/13)$

How do you condense log345 – log39log345 – log39?