How do you convert $(12, 7pi/4)$ to rectangular form?

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Answer 1 · 2016-02-20T06:31:59

$x=12 cos ((7pi)/4)=12*(1/sqrt2)=6sqrt2$

$y=12 sin ((7pi)/4)=12*(-1/sqrt2)=-6sqrt2$

Rectangular Form $(6sqrt2, -6sqrt2)$

Use $x=r cos theta$
Use $y=r sin theta$

$x=12 cos ((7pi)/4)=12*(1/sqrt2)=6sqrt2$

$y=12 sin ((7pi)/4)=12*(-1/sqrt2)=-6sqrt2$

Rectangular Form $(6sqrt2, -6sqrt2)$

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How do you convert (12, 7pi/4) (12, 7pi/4) to rectangular form?