How do you convert 2=(8x-7y)^2-7x into polar form?

1 Answer
Ayush S.
Jun 11, 2018

=>(15sin^2theta-56sin2theta+49)r^2-2=0

Explanation:

put x=rcostheta,y=rsintheta and solve
2=(8x-7y)^2-7x
=>2=64x^2+49y^2-112xy-7x
=>2=49(x^2+y^2)+15x^2-7x-xy
=>2=49r^2(sin^2theta+cos^2theta)+15r^2sin^2theta-56.2r^2sinthetacostheta
=>2=49r^2+15r^2sin^2theta-56r^2sin2theta
=>(15sin^2theta-56sin2theta+49)r^2-2=0

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