How do you convert 27.6 g #Ar# to atoms?

2 Answers
Jun 6, 2016

Answer:

Well, I know there are #"Avogadro's number"# of #"Ar"# atoms in a mass of #39.95*g#.

Explanation:

Thus #"Argon atoms"# #=# #(27.6*g)/(39.95*g*mol^-1)xx6.022xx10^23" argon atoms "mol^-1# #=# #??" argon atoms"#

Jun 6, 2016

Answer:

#4.15x10^23# atoms of Argon

Explanation:

To change 27.6 g of Argon to atoms we begin by converting the grams of Argon to moles using a conversion factor of 1 mole equal to the mass of Argon from the periodic table.

#27.6 cancel(g) ((1mol)/(39.95cancelg))=0.69 mol#

Now convert moles to atoms using Avogadro's number of #6.02x10^23#

#0.69cancel(mol)((6.02x10^23atms)/(1cancel(mol)))= #

#4.15x10^23# atoms of Argon