How do you convert $(3, -3sqrt3)$ to polar form?

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Answer 1 · 2016-05-03T10:30:43

In polar form $( 6, -60^@)$

$r= sqrt ((3^2 +(-3sqrt3)^2)$ $= sqrt 36 =6$ $theta= tan^-1((-3sqrt3)/3)=tan^-1(-sqrt3) = -60^@$
In polar form $(r,theta); (6, -60^@)$ [Ans]

How do you convert (3, -3sqrt3)(3, -3sqrt3) to polar form?