Question

How do you convert `3x - 2y= 6` into polar form?

Answer 1

`=> r = 6/(3cos(theta)-2sin(theta))`

Explanation:

When converting between polar and rectangular coordinates, we use the following equalities:
`{(x = rcos(theta)), (y = rsin(theta)):}`

Substituting these into the equation,

`3x - 2y = 6` becomes

`3rcos(theta) - 2rsin(theta) = 6`

`=> r(3cos(theta) - 2sin(theta)) = 6`

`=> r = 6/(3cos(theta)-2sin(theta))`