Question

How do you convert `(-4,pi/6)` into rectangular coordinates?

Answer 1

`x=-2sqrt3` and `y=-2`

Explanation:

To convert the polar coordinate `(-4, pi/6)` to rectangular coordinates, you have to use the following

`x=r cos theta` and `y=r sin theta`

given `r=-4` and `theta=pi/6`

`x=r cos theta=-4 *cos (pi/6)=-4*sqrt3/2=-2sqrt3`

`y=r sin theta=-4* sin (pi/6)=-4*(1/2)=-2`

God bless you...I hope my explanation helps...