# How do you convert 45°C to Fahrenheit?

Jun 2, 2016

Recall the formula to convert this.

$\setminus m a t h b f \left({T}_{C} = \frac{5}{9} \left({T}_{F} - 32\right)\right)$

Of course, ${T}_{C}$ is the temperature in $\text{^@ "C}$, and ${T}_{F}$ is the temperature in $\text{^@ "F}$.

Let's test this to make sure. I know that ${100}^{\circ} \text{C" = 212^@ "F}$ is the boiling point of water, so let's see if that works.

$\textcolor{g r e e n}{{T}_{C}} = \frac{5}{9} \left(212 - 32\right)$

$= \frac{5}{9} \left(180\right)$

$= 5 \cdot 20 = \textcolor{g r e e n}{{100}^{\circ} \text{C}}$

Yep. Now use it on ${45}^{\circ} \text{C}$.

$45 = \frac{5}{9} \left({T}_{F} - 32\right)$

$\frac{405}{5} = {T}_{F} - 32$

$81 + 32 = \textcolor{b l u e}{{113}^{\circ} \text{F} = {T}_{F}}$