How do you convert #(5, (3(pi))/2 ) # to rectangular form?

2 Answers
Jul 17, 2017

#(0,-5)#

Explanation:

#"to convert from "color(blue)"polar to rectangular form"#

#"that is " (r,theta)to(x,y)" where"#

#•color(white)(x)x=rcosthetacolor(white)(x);y=rsintheta"#

#"here "r=5" and " theta=(3pi)/2#

#rArrx=5cos((3pi)/2)=0#

#rArry=5sin((3pi)/2)=-5#

#rArr(5,(3pi)/2)to(0,-5)#

Jul 17, 2017

One should recognize the special case where the angle is #(3pi)/2#

This makes the x coordinate become 0 and makes y coordinate become length of the radial component, 5, overlaid upon the the negative y axis, -5.

Therefore, the point is #(0,-5)#