How do you convert #6y= 8x+2 # into a polar equation?
1 Answer
Feb 12, 2016
#r = 1/(3sintheta - 4costheta) #
Explanation:
using the formulae that links Cartesian to Polar coordinates.
#• x = rcostheta #
#• y = rsintheta# hence converting the question to
#6rsintheta =8rcostheta + 2 # and
# 6rsintheta - 8rcostheta = 2 # factorising gives :
# 2r(3sintheta - 4costheta) = 2# divide both sides by 2 :
#r(3sintheta - 4costheta) = 1 #
#rArr r = 1/(3sintheta - 4costheta) #
