How do you convert #(8, 5pi/4)# to rectangular form?

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Answer 1 · 2016-04-17T08:28:53

#x=-5,66#
#y=-5,66#

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#P=(8,5pi/4)#

#P=(x,y)" rectangular form"#

#r=8#

#x=8*cos (5pi/4)#

#x=-5,66#

#y=8*sin(5pi/4)#

#y=-5,66#