Question

How do you convert `9=(x+3)^2+(y-2)^2` into polar form?

Answer 1

`: r^2+2r(3costheta-2sintheta)+4=0`.

Explanation:

Simplifying the given eqn., it becomes `: x^2+y^2+6x-4y+4=0.`

To convert this cartsn. eqn. into polar, we use the conversion formula `;x=rcostheta, y=rsintheta, and, x^2+y^2=r^2`

Sub.ing, we get the eqn. in polar form as `: r^2+2r(3costheta-2sintheta)+4=0`.