Question

How do you convert `9=(x-6)^2+(y+2)^2` into polar form?

Answer 1

`r^2-4r(3costheta-sintheta)+31=0`.

Explanation:

We, first simplify the given eqn., and, get

`x^2+y^2-12x+4y+31=0..................(1)`.

For he conversion from cartesian to polar, we need the following

formulas `: x=rcostheta, y=rsintheta`.

Sub.ing, in `(1)`, we have,

`r^2-4r(3costheta-sintheta)+31=0`.