How do you convert $9x^3-2x-12y^2=8$ into polar form?

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Answer 1 · 2018-03-14T17:54:40

$9r^3cos^3theta-2rcostheta-12r^2sin^2theta=8$

$x=rcostheta$
$y=rsintheta$

$9(rcostheta)^3-2(rcostheta)-12(rsintheta)^2=8$

$9r^3cos^3theta-2rcostheta-12r^2sin^2theta=8$

How do you convert 9x^3-2x-12y^2=89x^3-2x-12y^2=8 into polar form?