How do you convert #r = 2tanthetasectheta# into cartesian form?

1 Answer

By substitution #y = 1/2*x^2#

Explanation:

First convert the expression into terms of #cos(theta)# and #sin(theta)#
#r = 2*sin(theta)/cos(theta) *1/cos(theta)#
#rcos^2(theta) = 2*sin(theta)#
Now the normal substitutions are #x=rcos(theta)# and #y=rsin(theta)#
#:. sin(theta) = y/r# and #cos(theta) = x/r#

Substituting these values into the expression above gives
#r*(x/r)^2 = 2*y/r#
#cancel(r)*x^2/r^cancel(2) = 2*y/r#
#x^2 = r*2*y/r =2* y#
#:.y =1/2 x^2#