How do you convert $r = 4 cos θ - 4 sin θ$ $r = 4costheta - 4sintheta$ to rectangular form?

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Answer 1 · 2016-10-06T14:00:58

Is a circle with origin at

$(2, - 2)$ $(2,-2)$ and radius $2 \sqrt{2}$ $2sqrt(2)$

Using the pass equations

${(x=rcostheta),(y=rsintheta):}$

$r = 4 x/r-4 y/r$ then

$r^2=4(x-y) = x^2+y^2$ or

$x^2-4x+y^2+4y=0$ which is a circle with origin at

$(2,-2)$ and radius $2sqrt(2)$

How do you convert r = 4costheta - 4sinthetar=4cosθ−4sinθr = 4costheta - 4sintheta to rectangular form?