How do you convert $r = - 5 csc θ$ $r=-5csctheta$ into rectangular equations?

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Answer 1 · 2016-09-25T10:47:08

$y = - 5$ $y=-5$

Given the pass equations

${(x=rcostheta),(y=rsintheta):}$

we have

$sqrt(x^2+y^2) = -5/sintheta = -5sqrt(x^2+y^2)/y$ or

$y = -5$

How do you convert r=-5cscthetar=−5cscθr=-5csctheta into rectangular equations?