Question

How do you convert `r=6/(2-3sin(theta))` to rectangular form?

Answer 1

`4x^2 -5y^2 -36y =36`

Explanation:

Simplify the expression by cross multiplication and write `2r=6+ 3rsin theta`

Or, `2r= 6+3y [ rsin theta=y]`

Now square both sides to have `4r^2= (6+3y)^2`

`4( x^2 +y^2)= 36 +36y +9y^2`

`4x^2 -5y^2 -36y =36`