How do you convert $r = 6 cos (θ)$ $r=6cos(theta)$ to rectangular form?

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How do you convert $r = 6 cos (θ)$ $r=6cos(theta)$ to rectangular form?

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Answer 1 · 2016-02-11T21:25:09

# x^2 + y^2 = 6x

Explanation:

using the formulae that links Polar to Cartesian coordinates.

$∙ r^{2} = x^{2} + y^{2}$ $• r^2 = x^2 + y^2$

$∙ x = r cos θ \Rightarrow cos θ = \frac{x}{r}$ $• x = rcostheta rArr costheta = x/r$

then here : $r = 6 cos θ \Rightarrow r = 6 \times \frac{x}{r}$ $r = 6 costheta rArr r = 6 xx x/r$

( multiply both sides by r )

hence $r^{2} = 6 x$ $r^2 = 6x$

$\Rightarrow x^{2} + y^{2} = 6 x$ $rArr x^2 + y^2 = 6x$

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How do you convert $r = 6 cos (θ)$ $r=6cos(theta)$ to rectangular form?

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Explanation:

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How do you convert r=6cos(theta)r=6cos(θ)r=6cos(theta) to rectangular form?

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Explanation:

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How do you convert $r = 6 cos (θ)$ $r=6cos(theta)$ to rectangular form?