How do you convert #r=6cos(theta)# to rectangular form?
1 Answer
Feb 11, 2016
# x^2 + y^2 = 6x
Explanation:
using the formulae that links Polar to Cartesian coordinates.
#• r^2 = x^2 + y^2 #
#• x = rcostheta rArr costheta = x/r # then here :
# r = 6 costheta rArr r = 6 xx x/r # ( multiply both sides by r )
hence
# r^2 = 6x #
#rArr x^2 + y^2 = 6x #
