Question

How do you convert `r=9/(1+3sin(θ))` into rectangular form?

Answer 1

`sqrt(x^2+y^2)+3y=9`

Explanation:

Divide both sides by `r`:

`1=9/(r+3rsin(theta))`

which you can rewrite as

`r+3rsin(theta)=9`

Since `r=sqrt(x^2+y^2)` and `y=rsin(theta)`, the equation becomes

`sqrt(x^2+y^2)+3y=9`