How do you convert #r=9sin(theta)# to rectangular form?

1 Answer
A. S. Adikesavan
Jun 6, 2016

#x^2+y^2-9y=0#. This represents the circle with center at #(0, 9/2)# and radius #9/2#.The circle touches the x-axis at the origin (0, 0)

Explanation:

#r=9 sin theta# represents the circle, with center at #(9/2, pi/2)# The origin (0, 0) in rectangular form is on this circle. This is the double #(0, 0) and (0. pi)#, in polar form.

For conversion to rectangular form, use #(x, y)=(r cos theta, r sintheta )# and #r^2=x^2+y^2#.

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