Question

How do you convert `r=9sin(theta)` to rectangular form?

Answer 1

`x^2+y^2-9y=0`. This represents the circle with center at `(0, 9/2)` and radius `9/2`.The circle touches the x-axis at the origin (0, 0)

Explanation:

`r=9 sin theta` represents the circle, with center at `(9/2, pi/2)` The origin (0, 0) in rectangular form is on this circle. This is the double `(0, 0) and (0. pi)`, in polar form.

For conversion to rectangular form, use `(x, y)=(r cos theta, r sintheta )` and `r^2=x^2+y^2`.