# How do you convert (sqrt3/2 ,1/2 ) into polar coordinates?

color(red)(r = 1, theta = (pi/6)^c " or " 30^@
$\left(x , y\right) = \left(\frac{\sqrt{3}}{2} , \frac{1}{2}\right)$
$r = \sqrt{{x}^{2} + {y}^{2}} = \sqrt{{\left(\frac{\sqrt{3}}{2}\right)}^{2} + {\left(\frac{1}{2}\right)}^{2}} = 1$
$\theta = \arctan \left(\frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}\right) = {\left(\frac{\pi}{6}\right)}^{c} \text{ or } {30}^{\circ}$