Question

How do you convert the angle `-408^circ16' 20''` in decimal degree form?

Answer 1

`= - 408.272^@`

Explanation:

`-408^@16^'20^('')` = `-408^@ + (16 *60)^('') +20^('')`

`= -408^@ + 980^('')`

`1^@ = 3600^('')`

Therefore,
`-408^@16^'20^('') = -408^@ + (980/3600)^@`

`= -408^@ + 0.272^@`

`= - 408.272^@`