How do you convert the rectangular point #(4,-4sqrt3)# into polar form?

1 Answer
Jul 27, 2017

#(8,-pi/3)#

Explanation:

#"to convert from "color(blue)"rectangular to polar"#

#"that is " (x,y)to(r,theta)" using"#

#•color(white)(x)r=sqrt(x^2+y^2)#

#•color(white)(x)theta=tan^-1(y/x);-pi < theta <=pi#

#"here "x=4" and " y=-4sqrt3#

#r=sqrt(4^2+(-4sqrt3)^2)=sqrt(16+48)=8#

#(4,-4sqrt3)" is in the fourth quadrant so we must ensure"#
#"that "theta" is in the fourth quadrant"#

#theta=tan^-1((4sqrt3)/4)#

#color(white)(theta)=tan^-1(sqrt3)=pi/3larrcolor(red)" related acute angle"#

#rArrtheta=-pi/3larrcolor(red)" in fourth quadrant"#

#rArr(4,-4sqrt3)to(8,-pi/3)#