How do you convert $theta=pi/6$ to rectangular form?

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Answer 1 · 2018-07-23T23:22:40

$y = x/sqrt3, x >=0 and y >=0$ See graph.

$theta = pi/6$ is the radial line, from the pole r = 0 ( origin ), in the

the direction $theta = pi/6$ ,

So, its slope is $tan (1/6pi) = 1/sqrt 3$ ,

and so, the Cartesian equation of the half-line is

$y = x/sqrt3, x >=0 and y >=0$ See graph.
graph{y-x/sqrt3=0[0 10 0 5]}

How do you convert theta=pi/6theta=pi/6 to rectangular form?