Question

How do you convert `theta=pi/6` to rectangular form?

Answer 1

`y = x/sqrt3, x >=0 and y >=0` See graph.

Explanation:

`theta = pi/6` is the radial line, from the pole r = 0 ( origin ), in the

the direction `theta = pi/6`,

So, its slope is `tan (1/6pi) = 1/sqrt 3`,

and so, the Cartesian equation of the half-line is

`y = x/sqrt3, x >=0 and y >=0` See graph.
graph{y-x/sqrt3=0[0 10 0 5]}