How do you convert $x^2 + (y -1)^2 = 1$ to polar form?

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How do you convert $x^2 + (y -1)^2 = 1$ to polar form?

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Answer 1 · 2016-02-11T06:55:04

$r = 2sin(theta)$

Explanation:

Transform using $x = rcos(theta) and y = rsin(theta)$ . r=0 is included in r = $2sin(theta).$ The equation represents a circle with center at polar coordinates $(1, pi/2)$ and radius 1.

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How do you convert $x^2 + (y -1)^2 = 1$ to polar form?

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Explanation:

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How do you convert x^2 + (y -1)^2 = 1 x^2 + (y -1)^2 = 1 to polar form?

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Explanation:

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How do you convert $x^2 + (y -1)^2 = 1$ to polar form?