How do you convert #x^2 + y^2 = 25# into polar form?
1 Answer
Dec 27, 2015
Substitute
#r = 5#
Explanation:
Substitute
#25 = x^2+y^2#
#=(r cos theta)^2 + (r sin theta)^2#
#=r^2 cos^2 theta + r^2 sin^2 theta#
#=r^2( cos^2 theta + sin^2 theta)#
#=r^2#
since
So
#r = sqrt(25) = 5#