Question

How do you convert `x/y=8-x` into polar form?

Answer 1

`r + (cot(theta)-8)sec(theta)=0`

Explanation:

The pass equations `x = r cos(theta), y = r sin(theta)` substituted into the cartesian equation gives:
`(r cos(theta))/(r sin(theta)) = 8 - r cos(theta)`. Simplifiying and solving for `r`
`r + (cot(theta)-8)sec(theta)=0`