How do you convert y= 3x^2+3x-y^2 y=3x2+3xy2 into a polar equation?

1 Answer
Jul 3, 2018

Polar equation of hyperbola is ,
r =(3 cos theta - sin theta)/(sin^2 theta-3 cos ^2 theta) r=3cosθsinθsin2θ3cos2θ

Explanation:

In rectangular - polar conversion,

r^2=x^2+y^2 , x= r cos theta , y= r sin theta r2=x2+y2,x=rcosθ,y=rsinθ

y= 3 x^2+3 x-y^2y=3x2+3xy2 or

y^2 + y= 3 x^2+3 xy2+y=3x2+3x or

y(y+1)= 3 x(x+1)y(y+1)=3x(x+1) or

cancelr sin theta (r sin theta +1)= 3 cancelr cos theta( r cos theta+1) or

r sin^2 theta+sin theta = 3 r cos ^2 theta+3 cos theta or

r sin^2 theta-3 r cos ^2 theta=3 cos theta - sin theta or

r (sin^2 theta-3 cos ^2 theta) =3 cos theta - sin theta or

r =(3 cos theta - sin theta)/(sin^2 theta-3 cos ^2 theta)

Polar equation of hyperbola is ,

r =(3 cos theta - sin theta)/(sin^2 theta-3 cos ^2 theta)

graph{y=3 x^2+3 x-y^2 [-10, 10, -5, 5]} [Ans]