How do you convert $-y=3y^2-x^2 +x^3$ into a polar equation?

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Answer 1 · 2016-04-15T20:58:44

$0=3r^2sin^2theta+rsintheta+r^3cos^3theta-r^2cos^2theta$

$0=3y^2+y+x^3-x^2$
use the formulas:
$x=rcostheta and y= rsin theta$

$0=3r^2sin^2theta+rsintheta+r^3cos^3theta-r^2cos^2theta$

How do you convert -y=3y^2-x^2 +x^3 -y=3y^2-x^2 +x^3 into a polar equation?