How do you correctly round this problem #(30.00 g)/ (10.0 mL)#?
Please see the step process below...
Firstly, you have to convert the
Though it depends on what you want your final unit to be..
But in this case, am going to convert it;
Hence we have;
Well, you are dividing, so you keep the fewest number of significant figures.
All trailing zeroes after the decimal place are significant, and zeroes sandwiched between a decimal place and a nonzero digit are also significant.
So you just get:
#"30.00 g"/"10.0 mL" = color(blue)("3.00 g"/"mL")#