Question

How do you create a polynomial with Degree 3, 2 Positive real zeros, 1 negative real zero, 0 complex zeros?

Answer 1

`f(x)=(x-a)(x-b)(x+c)` for some arbitrary selection of `a, b, c > 0`

Explanation:

For example `a=2, b=3, c=5`

`f(x)=(x-2)(x-3)(x+5)`
will have zeros at `(+2)`, `(+3)` and `(-5)`