# How do you create a polynomial with Degree 3, 2 Positive real zeros, 1 negative real zero, 0 complex zeros?

Dec 26, 2015

$f \left(x\right) = \left(x - a\right) \left(x - b\right) \left(x + c\right)$ for some arbitrary selection of $a , b , c > 0$
For example $a = 2 , b = 3 , c = 5$
$f \left(x\right) = \left(x - 2\right) \left(x - 3\right) \left(x + 5\right)$
will have zeros at $\left(+ 2\right)$, $\left(+ 3\right)$ and $\left(- 5\right)$