How do you create a table of values to graph #2x-6y=12#?

1 Answer
Nov 10, 2016

Answer:

Please see below.

Explanation:

It is a linear equation, so it may be appropriate and sufficient to the graphselect three points wide apart to draw the graph.

Let #x=0#, then we have #0-6y=12# or #y=12/(-6)=-2# and hence our first point is #A(0,-2)#.

Next let #y=0#, then we have #2x-0=12# or #x=12/2=6# and hence our second point is #B(6,0)#.

Let us select another point with #x=-6#, then we have #2xx(-6)-6y=12# or #-12-6y=12# or #6y=-24# or #y=24/(-6)=-4# and our tird point is #C(-6,-4)#.

Table could be

Table#color(white)(XXXXX)xcolor(white)(XXXXX)y#

A#color(white)(XXXXXXX)0color(white)(XXXX)-2#

B#color(white)(XXXXXXX)6color(white)(XXXXX)0#

A#color(white)(XXXXXX)-6color(white)(XXXX)-4#

Now just join points to get the graph, which appears as below.
graph{2x-6y=12 [-9.75, 10.25, -7.44, 2.56]}