How do you determine if 2sin(x)cos(x)tan^2(x)2sin(x)cos(x)tan2(x) is an even or odd function?

1 Answer
A. S. Adikesavan
Apr 14, 2016

Odd

Explanation:

Change x to -x−x in f(x).

If f(-x)=-f(x)f(−x)=−f(x), the function is odd.
If f(-x)=f(x)f(−x)=f(x), the function is even.

sin(-x)=-sin x, cos(-x)=cos x and tan(-x)=-tan x. Also, (-1)^2=1sin(−x)=−sinx,cos(−x)=cosxandtan(−x)=−tanx.Also,(−1)2=1

Here, f(-x)=-f(x)f(−x)=−f(x). So, the given function is odd. .

Related questions
See all questions in Introduction to Twelve Basic Functions
Impact of this question
1219 views around the world
You can reuse this answer
Creative Commons License