Question

How do you determine if `f(x)= x^2 + 2` is an even or odd function?

Answer 1

`f(x)=x^2+2` is an even function.

Explanation:

If `f(-x)=-f(x)` then the function is odd, but if `f(-x)=f(x)`, the function is even,

In the instance given, `f(x)=x^2+2` and

`f(-x)=(-x)^2+2=x^2+2=f(x)`, hence

`f(x)=x^2+2` is an even function.