How do you determine if #f(x)= | x^3 |# is an even or odd function?

1 Answer
Mar 22, 2016

#f# is an even function since #f(-x)=f(x) AA x in RR#.

Explanation:

By definition,
#f# is an even function if #f(-x)=f(x) AA x in RR#.
#f# is an odd function if #f(-x)=-f(x) AAx in RR#.

Since the absolute value function always outputs a positive value irrespective of the input, it is clear that in this case, #f(-x)=f(x) AAx in RR#.
This is precisely the definition of an even function and hence it is an even function.