How do you determine if sin2(x) is an even or odd function?

1 Answer
Jan 11, 2017

sin2(x) is an even function.

Explanation:

A function f(x) is even if f(x)=f(x) and function is odd if f(x)=x.

As f(x)=sin2(x)

f(x)=sin2(x)

= (sin(x))2

= (sin(x))2

= sin2(x)

Hence sin2(x) is an even function.