How do you determine if #y=1-sin(x)# is an even or odd function?

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Answer 1 · 2016-03-25T08:43:11

Function is neither odd nor even.

If #f(-x)=f(x)# then the function is even,

but if #f(-x)=-f(x)# then the function is odd.

As #f(x)=1-sinx#

#f(-x)=1-sin(-x)=1-(-sinx)=1+sinx#

As #-f(x)=-1+sinx#,

hence neither #f(-x)=f(x)# nor #f(-x)=-f(x)#

Hence the given function is neither odd nor even.