How do you determine the amplitude, period, and shifts to graph #y=-sinx+2#?

1 Answer
Jun 3, 2016

#1,2pi,"vertical shift of"+2#

Explanation:

The standard form of the #color(blue)"sine wave function"# is

#color(red)(|bar(ul(color(white)(a/a)color(black)(y=asin(bx+c)+d)color(white)(a/a)|)))#

where amplitude = |a| , period#=(2pi)/b#

c is the horizontal shift and d , the vertical shift

here a = -1 , b = 1 , c = 0 and d = 2

hence amplitude = |-1| = 1 , period#=(2pi)/1=2pi#

there is no horizontal shift and vertical shift of #((0),(2))#