# How do you determine the correct molecular shapes of GeF_4, SeF_4, and XeF_4?

We got ${\text{GeF}}_{4}$...there are $\text{4 bonding orbitals}$ around $G e$...this is tetrahedral...,i.e. an analogue of ${\text{SiCl}}_{4}$ or ${\text{CCl}}_{4}$.
And we got $S e {F}_{4}$...there are 2 lone pair electrons, and $4 \times S e - F$, FIVE electron pairs around selenium...the electronic geometry is trigonal bipyramidal...with the lone pair occupying an equatorial site. the fluorines would conformationally mobile …
And we $X e {F}_{4}$ we gots SIX electron pairs around xenon....electronic structure is OCTAHEDRAL; molecular geometry is square planar.